PLEASE HELP!!!
A salesman mixed two kinds of candies worth $1.25 and $1.6 a pound, respectively. He made a mixture of 70 pounds to sell at $1.4 a pound. How many pounds of each did he use?

Respuesta :

Answer:

40 pounds of candy worth $1.25

30 pounds of candy worth $1.60

Step-by-step explanation:

1.25x + 112 -1.6x = 98

-0.35x = -14

0.35x = 14

x= 40 pounds

70 pounds in total - 40 pounds = 30

y = 30 pounds

The quantity of each candy can be calculated by using algebraic expression.

The quantity of candy type 1 is [tex]40 \:\rm pound[/tex] and type 2 is [tex]30\:\rm pounds[/tex].

Given:

The cost of type I is [tex]\$1.25[/tex].

The cost of type II is [tex]\$1.6[/tex].

The total candies is [tex]70\:\rm pounds[/tex].

Let [tex]x[/tex] pounds is the type I candies and [tex]y[/tex] pounds is the type II candies.

The salesman mixed two candies,

[tex]x+y=70\\x=70-y[/tex]

As per the question statement sum of type I candies multiply by cost of type I and  type II candies multiply by cost of type II.

[tex]1.25x + 1.6y = 70\times 1.40\\1.25x + 1.6y = 98[/tex]

Substitute [tex](70-y)[/tex] for [tex]x[/tex].

[tex]\begin{aligned}1.25(70-y)+1.6y=98\\87.5-1.25y+1.6y=98\\0.35y=10.5\\y=30\\\end[/tex]

Now, find the value of [tex]x[/tex].

[tex]x=70-30\\x=40[/tex]

Thus, the quantity of candy type 1 is [tex]40 \:\rm pound[/tex] and type 2 is [tex]30\:\rm pounds[/tex].

Learn more about algebraic expression here:

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