Answer:
Dwayne worked 20 hours for first job and 25 hours for second job.
Step-by-step explanation:
Let the number of hours worked by Dwayne in first job = x
Let the number of hours worked by Dwayne in second job = y
Then, [tex]\[x + y = 45\][/tex] ----------------- (1)
First job pays $14 per hour
Second job pays $10 per hour
=> [tex]\[14x + 10y = 530\][/tex] ------------- (2)
Solving (1) and (2):
[tex]\[y = 45 - x\][/tex]
Substituting in (2):
[tex]\[14x + 10 (45-x) = 530\][/tex]
=> [tex]\[14x + 450- 10x = 530\][/tex]
=> [tex]\[4x = 530 - 450\][/tex]
=> [tex]\[4x = 80\][/tex]
=> [tex]\[x = 20\][/tex]
Substituting in (1):
[tex]\[y = 45 - x\][/tex]
=> [tex]\[y = 45 - 20\][/tex]
=> [tex]\[y = 25 \][/tex]
