Respuesta :
Answer:
[tex]F=\frac{s^2_1}{s^2_2}=\frac{0.2211^2}{0.0768^2}=8.28[/tex]
[tex]p_v =2*P(F_{24,21}>8.28)=7.22x10^{-6}[/tex]
Since the [tex]p_v < \alpha[/tex] we have enough evidence to reject the null hypothesis. And we can say that we have enough evidence to conclude that the variation between the two machines is significant at 5% of significance.
Step-by-step explanation:
Data given and notation
Machine 1: 2.95 3.45 3.50 3.75 3.48 3.26 3.33 3.20 3.16 3.20 3.22 3.38 3.90 3.36 3.25 3.28 3.20 3.22 2.98 3.45 3.70 3.34 3.18 3.35 3.12
Machine 2: 3.22 3.30 3.34 3.28 3.29 3.25 3.30 3.27 3.38 3.34 3.35 3.19 3.35 3.05 3.36 3.28 3.30 3.28 3.30 3.20 3.16 3.33
[tex]n_1 = 23 [/tex] represent the sampe size for machine 1
[tex]n_2 =22[/tex] represent the sample size for machine 2
[tex]\bar X_1 =3.33[/tex] represent the sample mean for machine 1
[tex]\bar X_2 =3.28[/tex] represent the sample mean for machine 2
[tex]s_1 = 0.2211[/tex] represent the sample deviation for machine 1
[tex]s^2_1 = 0.049[/tex] represent the sample variance for machine 1
[tex]s_2 = 0.0768[/tex] represent the sample deviation for machine 2
[tex]s^2_2 = 0.00690[/tex] represent the sample variance for machine 2
[tex]\alpha=0.05[/tex] represent the significance level provided
Confidence =0.95 or 95%
F test is a statistical test that uses a F Statistic to compare two population variances, with the sample deviations s1 and s2. The F statistic is always positive number since the variance it's always higher than 0. The statistic is given by:
[tex]F=\frac{s^2_1}{s^2_2}[/tex]
Solution to the problem
System of hypothesis
We want to determine whether there is a significant difference between thevariances in the bag weights for the two machines , so the system of hypothesis are:
H0: [tex] \sigma^2_1 = \sigma^2_2[/tex]
H1: [tex] \sigma^2_1 \neq \sigma^2_2[/tex]
Calculate the statistic
Now we can calculate the statistic like this:
[tex]F=\frac{s^2_1}{s^2_2}=\frac{0.2211^2}{0.0768^2}=8.28[/tex]
Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have [tex]n_1 -1 =25-1=24[/tex] and for the denominator we have [tex]n_2 -1 =22-1=21[/tex] and the F statistic have 24 degrees of freedom for the numerator and 21 for the denominator. And the P value is given by:
P value
[tex]p_v =2*P(F_{24,21}>8.28)=7.22x10^{-6}[/tex]
And we can use the following excel code to find the p value:"=2*(1-F.DIST(8.2838,24,21,TRUE))"
Conclusion
Since the [tex]p_v < \alpha[/tex] we have enough evidence to reject the null hypothesis. And we can say that we have enough evidence to conclude that the variation between the two machines is significant at 5% of significance.