Answer:
The new electric field at point P is E/4.
Explanation:
It is given that,
The magnitude of electric field due to the sheet is E at a point P. The electric field due to a non conducting sheet is given by :
[tex]E=\dfrac{q}{2A\epsilon_o}[/tex]
A is the area of square sheet
For the square sheet, [tex]A=d^2[/tex], l is the side of square
[tex]E=\dfrac{q}{2d^2\epsilon_o}[/tex]...........(1)
If the sheet is now stretched so that its sides have length 2d, electric field is E'
[tex]E'=\dfrac{q}{2(2d)^2\epsilon_o}[/tex].........(2)
Taking ratios of equation (1) and (2) as :
[tex]\dfrac{E}{E'}=\dfrac{4}{1}[/tex]
[tex]E'=\dfrac{E}{4}[/tex]
If the sheet is now stretched so that its sides have length 2d, the new electric field at point P is E/4.
