Answer:
De broglie wavelength will be 0.727 nm
Explanation:
We have given speed of the electron [tex]v=10^6m/sec[/tex]
Mass of the electron [tex]m=9.11\times 10^{-31}kg[/tex]
Plank's constant [tex]h=6.624\times 10^{-34}Js[/tex]
We have to find the De Broglie wavelength
De Broglie wavelength is given by [tex]\lambda =\frac{h}{mv}=\frac{6.624\times 10^{-34}}{9.11\times 10^{-31}\times 10^6}=0.727\times 10^{-9}m[/tex]
So wavelength will be 0.727 nm
