Answer:
c. [tex]\left[\begin{array}{ccc}3&-8&-2\\0&5&6\end{array}\right][/tex]
Step-by-step explanation:
Given:
Vertex of triangle:
A(6,-2)
B(-5,3)
C(1,4)
The triangle ABC is translated 3 units left and 2 units up.
To find the co-ordinates of the vertex of the translated triangle in matrix form.
Solution:
Transformation sequence occurring can be given as:
3 units left shift would decrease the x-coordinate by 3 units.
2 units upwards shift would increase y-coordinate by 2 units.
So, we have
[tex](x,y)\rightarrow (x-3,y+2)[/tex]
The Image points will be given as:
[tex]A(6,-2)\rightarrow A'(6-3,-2+2)=A'(3,0)[/tex]
[tex]B(-5,3)\rightarrow B'(-5-3,3+2)=B'(-8,5)[/tex]
[tex]C(1,4)\rightarrow C'(1-3,4+2)=C'(-2,6)[/tex]
The image points in matrix form can be given as:
[tex]\left[\begin{array}{ccc}A'&B'&C'\\x_1&x_2&x_3\\y_1&y_2&y_3\end{array}\right][/tex]
Plugging in the points the matrix can be written as:
[tex]\left[\begin{array}{ccc}3&-8&-2\\0&5&6\end{array}\right][/tex] (Answer)
