Answer:
The probability that the experimenter’s point estimate of p will be within the interval (0.62, 0.64) is 0.72
Step-by-step explanation:
To find a probability for the confidence interval we need to calculate z-statistic of the margin of error of the confidence interval.
margin of error for (0.62, 0.64) with p=0.63 is 0.01
Margin of error (ME) can be calculated using the equation
[tex]ME=\frac{z*\sqrt{p*(1-p)}}{\sqrt{N} }[/tex] where
Then solving [tex]0.01=\frac{z*\sqrt{0.63*0.37}}{\sqrt{300} }[/tex] gives z≈0.3587
two tailed p-value for z≈0.3587 is 0.72.
Thus, the probability that the experimenter’s point estimate of p will be within the interval (0.62, 0.64) is 0.72
