Answer:
the acceleration due to gravity is g = 6 m/s² (option C)
Explanation:
if we ignore air friction, the height h an object falls under a gravity g is calculated through:
h =h₀ + v₀*t - 1/2*g*t²
where
t= time to reach a height h
v₀ = initial vertical velocity of the object =0 m/s( since is released from rest)
g = gravity
h₀ = initial height = 3m
if the object starts at height h₀ = 3 m then it finishes at height h= 0 m when it falls 3 meters.
then since v₀=0 m/s :
h =h₀ - 1/2*g*t²
replacing values
0 = 3 m - 1/2*g*(1 s)²
g= 2*( 3m - 0m)/(1 s)² = 6 m/s²
g = 6 m/s² (option C)
