Answer:
0.631 mm
Explanation:
Strain=[tex]\frac {\triangle L}{L}=1%[/tex] hence 0.01
Stress=strain* Young’s modulus hence
Stress=[tex]0.01*3.2 Gpa=32 N/mm^{2}[/tex]
But stress, [tex]\sigma=\frac {P}{A}=\frac {P}{0.25\pi d^{2}}[/tex]
Making d the subject then
[tex]d=\sqrt {\frac {P}{0.25\pi \sigma}}[/tex]
[tex]d=\sqrt {\frac {10}{0.25\pi*32}}\approx 0.631 mm[/tex]
