Answer:
Distance traveled will be 65.3 m
So option (c) will be correct option
Explanation:
We have given mass of the car m = 1000 kg
Velocity v = 32 m /sec
Coefficient of friction = 0.8
The force on the car will be equal to frictional force
So [tex]ma=\mu mg[/tex]
[tex]a=\mu g=0.8\times 9.8=7.84m/sec^2[/tex]
When the car stops its final velocity will be zero
According to third equation of motion we know that
[tex]v^2=u^2+2as[/tex]
So [tex]s=\frac{u^2}{2a}=\frac{32^2}{2\times 7.84}=65.30m[/tex]
So option (c) will be correct answer
