Consider a reversible heat engine that employs a hot reservoir at a temperature of 610 K and a cold reservoir at 290 K. (a) What is the entropy change of the hot reservoir during a period in which 4730 J is extracted from the hot reservoir? 7.75 J/K

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johncorey7208 johncorey7208

24-12-2019
Physics

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Consider a reversible heat engine that employs a hot reservoir at a temperature of 610 K and a cold reservoir at 290 K. (a) What is the entropy change of the hot reservoir during a period in which 4730 J is extracted from the hot reservoir? 7.75 J/K

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cjmejiab cjmejiab · Answer 1 · 2019-12-24T05:32:36+01:00

To solve this problem it is necessary that we start from the definition of entropy as a function of heat and temperature exchange. Mathematically this thermodynamic expression can be described as

[tex]\Delta S = \frac{Q}{T}[/tex]

Where,

Q= Heat exchange

T = Temperature

Since we look for entropy in the hot reservoir, and considering our given values we have to

[tex]T_H = 610K\\T_C = 290K \\Q_H = 4730J[/tex]

Replacing we have:

[tex]\Delta S_H= \frac{Q_H}{T_H}[/tex]

[tex]\Delta S_H = \frac{4730J}{610K}[/tex]

[tex]\Delta S_H = 7.754J/K[/tex]

Therefore the final change in the entropy is 7.75J/K