Answer:
t = 2.13 s
Explanation:
given,
height of the building = 22.3 m
horizontal distance = 127 m
acceleration due to gravity = 9.8 m/s²
time for which ball is in motion = ?
using equation of motion
[tex]s = u t + \dfrac{1}{2}gt^2[/tex]
initial velocity is zero
[tex]s = \dfrac{1}{2}gt^2[/tex]
[tex]t = \sqrt{\dfrac{2s}{g}}[/tex]
[tex]t = \sqrt{\dfrac{2\times 22.3}{9.8}}[/tex]
t = √4.551
t = 2.13 s
