Answer:
C) 28 in.
Step-by-step explanation:
Given:
Hooke's Law for an elastic spring states that "the distance a spring stretches varies directly as the force to be applied."
Hence we can say that;
F ∝ D
F = k . D
where,
F ⇒ Force applied
D⇒ Distance of spring
k⇒ constant
Now Given:
Force (F) = 15 pounds
Distance of Spring (D) = 7 inches
Substituting the values in above equation we get;
[tex]15=k\times 7\\\\k = \frac{15}{7} \approx 2.143\ pounds/inches[/tex]
Now we need to find Distance of the spring stretched when Force is 60 pounds.
[tex]F =kD\\\\D = \frac{F}{k}[/tex]
Substituting the values we get;
[tex]D = \frac{60}{2.143} \approx 28\ inches[/tex]
Hence the distance of spring stretched will be 28 inches when a force of 60 pounds applied to it.
