Answer:
The initial velocity of the projectile is 50 meters per minute
Explanation:
The equation that describes the height (h on meters) of the projectile as a function of time (t in minutes) is:
[tex] h(t)=\left(-5\frac{m}{min^{2}}\right)\,t^{2}+v_{0}\,t [/tex](1)
We already know at 10 minutes the projectile reaches the ground, so if we assume our coordinate system on the ground that implies h(10 min)=0m, using this on (1):
[tex] 0=\left(-5\frac{m}{min^{2}}\right)\,(10\,min)^{2}+v_{0}\,(10\,min) [/tex]
solving for [tex] v_{0} [/tex]:
[tex]v_{0}=\frac{\left(5\frac{m}{min^{2}}\right)\,(10\,min)^{2}}{(10\,min)}=50\,\frac{m}{min} [/tex]
Note: It’s important to have a careful use of units in this kind of problem to avoid errors in the units of our answers, if we are calculating velocity we should get velocity units.
