Answer:
D. 1 atm
Explanation:
pressure P1 = 1.5 atm = 1.5 x 101325 = 151987.5 N/m^{2}
speed V = 1 m/s
speed U = 10 m/s
pressure P2 = ?
applying Bernoulli's equation we can find the pressure P2
[tex]\frac{1}{2}ρv^{2}+P1=\frac{1}{2}ρu^{2}+P2[/tex]
[tex]\frac{1}{2}ρv^{2}-\frac{1}{2}ρu^{2}+P1= P2[/tex]
[tex]P2=\frac{1}{2}ρ(v^{2}-u^{2})+P1[/tex]
where ρ is the density of water = 1000 kg/m^{3}
[tex]P2=\frac{1}{2}x1000x(1^{2}-10^{2})+151987.5 [/tex]
[tex]P2=\frac{1}{2}x1000x(-99)+151987.5[/tex]
P2 = 102487.7 N/m^{2}
P2 = 102487.7 / 101325 = 1.01 atm = 1 atm
