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What are the intercepts of the function?
The x-intercepts are
Consider the function f(x) = x2 + 12x + 11.
x-intercepts:
0=x2 + 12x +11
0 = (x + 1)(x+ 11)
The y-intercept is
y-intercept
f(0) = (0)2 + 12(0) + 11

Respuesta :

Answer:

-1 and -11 are x-intercepts,  y-intercept = 11.

Step-by-step explanation:

given function: f(x) = x^2 + 12x + 11.

  • x-intercepts: value of the function when f(x) is zero.

so, 0= x^2 + 12x + 11.

write 12x as 11x+x,

x^2 + x+11x + 11=0

common terms,

0 = (x + 1)(x+ 11)

  • so, -1 and -11 are x-intercepts. because, when we substitute these as x values, the f(x) will be zero.
  • y-intercept: value of the function f(x) when x=0 i.e, f(0).

so,  y-intercept= 0+0+11 = 11.

sharpesescape

Answer: ( -1, 0) and ( - 11, 0) the y -intercept is (0, 11) which is A for the x - intercepts are, & D for the y - intercept is (0, 11)

Step-by-step explanation: