Answer:
31677.2 lb
Explanation:
mass of hammer (m) = 3.7 lb
initial velocity (u) = 5.8 ft/s
final velocity (v) = 0
time (t) = 0.00068 s
acceleration due to gravity (g) 32 ft/s^{2}
force = m x ( a + g )
where
from v = u + at
a = (v-u)/ t
a = (0-5.8)/0.00068 = -8529.4 ( the negative sign showa the its decelerating)
we can substitute all required values into force= m x (a+g)
force = 3.7 x (8529.4 + 32) = 31677.2 lb
The force exerted by the hammer is 31677.2 lb
Given information:
mass of hammer, m = 3.7 lb
initial velocity, u = 5.8 ft/s
final velocity, v = 0
time taken t = 0.00068 s
acceleration due to gravity, g = 32 ft/s²
The total force exerted by the hammer is given by:
F = m(a + g)
where
g is the acceleration due to gravity = 32 ft/s²
a is the acceleration of the hammer
from first equation of motion we get that:
v = u + at
a = (v-u)/ t
a = (0-5.8)/0.00068
a = -8529.4
the negative sign shows deceleration
So the force exerted is:
F = 3.7 (8529.4 + 32)
F = 31677.2 lb
Learn more about equations of motion:
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