) A skier starts down a frictionless 32° slope. After a vertical drop of 25 m, the slope temporarily levels out and then slopes down at 20°, dropping an additional 38 m vertically before leveling out again. Find the skier’s speed on the two level stretches

Respuesta :

Answer:

The skier’s speed on the two level stretches are 22.13 m/s and 27.29 m/s.

Explanation:

Given that,

Slope down = 32°

Height = 25 m

Before leveling,

Slope down = 20°

Height = 38 m

We need to calculate the skier’s speed on the two level stretches

Using formula of energy

[tex]P.E=K.E[/tex]

[tex]mgh=\dfrac{1}{2}mv^2[/tex]

[tex]v=\sqrt{2gh}[/tex]

For first stretch,

Height = 25 m

Put the value into the formula

[tex]v=\sqrt{2\times9.8\times25}[/tex]

[tex]v=22.13\ m/s[/tex]

For second stretch,

Height = 38 m

Put the value into the formula

[tex]v=\sqrt{2\times9.8\times38}[/tex]

[tex]v=27.29\ m/s[/tex]

Hence, The skier’s speed on the two level stretches are 22.13 m/s and 27.29 m/s.