Answer:
The canyon is approximately 314 meters away
Explanation:
Speed of Sound
If we emit sounds in an open space where a large obstacle (like a mountain) is expected to return the sounds, then it will travel forth and back at a given speed for a certain time. We can assume the speed of sound is constant, so we could know the approximate distance of the mountain (or canyon in our case) by the known formula.
[tex]x=v_st[/tex]
Where [tex]v_s[/tex] is the speed of sound and t is half the time we hear our echo.
The speed of sound in m/s can be calculated from the approximate formula in terms of the temperature T in degrees Celsius
[tex]v_s=331.3+0.606T[/tex]
We have [tex]T=29.5^oC[/tex], so
[tex]v_s=331.3+0.606(29.5)[/tex]
[tex]v_s=349.177\ m/s[/tex]
Let's compute x, for t=1.8/2=0.9 seconds
[tex]x=v_st=(349.177)(0.9)[/tex]
[tex]x=314.26\ m[/tex]
The canyon is approximately 314 meters away
