A point on the terminal side of an angle theta is given. Find the exact value of each of the six trigonometric functions of theta. (-2,-5) sin theta = cos theta = tan theta = csc theta = sec theta = cot theta =

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Answer:

Step-by-step explanation:

Plot that point in the x/y coordinate plane to see that it sits in the third quadrant.  From the point, draw a line to the origin, constructing a right triangle.  The side adjacent to the angle is -2, the side across from the angle is -5, so we need to find the length of the hypotenuse using Pythagorean's Theorem:

[tex]c^2=(-5)^2+(-2)^2[/tex] and

[tex]c^2=25+4[/tex] so

[tex]c=\sqrt{29}[/tex]

That means that

[tex]sin\theta=-\frac{5}{\sqrt{29} }=-\frac{5\sqrt{29} }{29}[/tex] and

[tex]csc\theta=-\frac{\sqrt{29} }{5}[/tex]

That means that

[tex]cos\theta=-\frac{2}{\sqrt{29} }=-\frac{2\sqrt{29} }{29}[/tex] and

[tex]sec\theta=-\frac{\sqrt{29} }{2}[/tex]

It also means that

[tex]tan\theta=\frac{5}{2}[/tex] and

[tex]cot\theta=\frac{2}{5}[/tex]