Answer:
The molarity of the solution is 7.4 mol/L
Explanation:
From the question above
0.400 ml of water contains 1.00 g of hydrochloride form of cocaine
Therefore 1000 ml of water will contain x g of hydrochloride form of cocaine
x = 1000 / 0.400
x = 2500 g
2500g of hydrochloride form of cocaine is present in 1000 ml of water.
Mole of hydrochloride form of cocaine = mass /molar mass of hydrochloride
Mole of hydrochloride form of cocaine = 2500/339.8
= 7.4 mol
Molarity = mol/ volume in liter (L)
molarity = 7.4 /1
Molarity = 7.4 mol/L
Answer:
[tex]M=7.35M[/tex]
Explanation:
Hello,
In this case, the cocaine hydrochloride whose molecular formula is:
[tex]C_{17}H_{22}ClNO_4[/tex]
Has a molar mass of 339.8 g/mol, for that reason, in 1.00 g there are the following moles:
[tex]n=1.00gC_{17}H_{22}ClNO_4*\frac{1molC_{17}H_{22}ClNO_4}{339.8gC_{17}H_{22}ClNO_4} =2.94x10^{-3}molC_{17}H_{22}ClNO_4[/tex]
Such calculations are performed at the saturation condition with which the molarity is obtained as:
[tex]M=\frac{n}{V}[/tex]
Thus, the volume in liters is:
[tex]V=0.4mL*\frac{1L}{1000mL} =4x10^{-4}L[/tex]
As we assume the volume does not change when the cocaine hydrochloride is added to the water, therefore, we obtain the molarity:
[tex]M=\frac{2.94x10^{-3}molC_{17}H_{22}ClNO_4}{4.00x10^{-4}L} =7.35M[/tex]
Best regards.
