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A population of mice has black or brown hair. The gene for black hair color (B) is dominant over brown (b). If 16% of the mice are homozygous black and 24% are heterozygous black, what would be the frequency of each allele?

Respuesta :

Diatonic254

B = 0.4

b = 0.6

Explanation:

From the question we derive that;

BB = 16%

Bb = 24%

The gene frequency for BB = 16/100 = 0.16

To find allelic frequency of B;

B = √0.16 = 0.4

Remember Hardy Weinberg rule that all allelic frequencies of a gene must sum up to 1;

p + q = 1

If p = 0.4

q = 1 – 0.4 = 0.6

b = 0.6

Learn More:

For more on allelic /genetic frequencies check out;

https://brainly.com/question/9916141

https://brainly.com/question/12021027

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