Respuesta :
Answer:
The final temperature is:- 7428571463.57 °C
Explanation:
The expression for the calculation of heat is shown below as:-
[tex]Q=m\times C\times \Delta T[/tex]
Where,
[tex]Q[/tex] is the heat absorbed/released
m is the mass
C is the specific heat capacity
[tex]\Delta T[/tex] is the temperature change
Thus, given that:-
Mass of water = 1.75 mg = 0.00175 g ( 1 g = 0.001 mg)
Specific heat of water = 4.18 J/g°C
Initial temperature = 35 °C
Final temperature = x °C
[tex]\Delta T=(x-35)\ ^0C/tex]
Q = [tex]1.3\times 10^4[/tex] kcal
Also, 1 kcal = 4.18 kJ = [tex]4.18\times 10^3[/tex] J
So, Q = [tex]1.3\times 10^4\times 4.18\times 10^3[/tex] J = 54340000 J
So,
[tex]54340000=0.00175\times 4.18\times (x-35)[/tex]
[tex]0.00175\times \:4.18\left(x-35\right)=54340000[/tex]
[tex]x-35=\frac{54340000}{0.007315}[/tex]
[tex]x=7428571463.57[/tex]
Thus, the final temperature is:- 7428571463.57 °C
