Answer
given,
capacitance = C = 3.4-µF
inductance = L = 0.08 H
frequency is expressed as
[tex]f = \dfrac{1}{2\pi\sqrt{LC}}[/tex]
time period
[tex]T = \dfrac{1}{f}=2\pi\sqrt{LC}[/tex]
after time T/4 current reach maximum
[tex]t = \dfrac{T}{4}[/tex]
[tex]t = \dfrac{2\pi\sqrt{LC}}{4}[/tex]
[tex]t = \dfrac{2\pi\sqrt{0.08 \times 3.4 \times 10^{-6}}}{4}[/tex]
t = 8.2 x 10⁻⁴ s
t = 0.82 ms
b) using law of conservation
[tex]\dfrac{1}{2}CV^2=\dfrac{1}{2}LI^2[/tex]
[tex]I^2 = \dfrac{CV^2}{L}[/tex]
[tex]I^2 = \dfrac{C}{L}\dfrac{Q^2}{C^2}[/tex]
[tex]I =\sqrt{\dfrac{Q^2}{CL}}[/tex]
[tex]I =\sqrt{\dfrac{(5.4 \times 10^{-6})^2}{0.08 \times 3.4 \times 10^{-6}}}[/tex]
I = 0.010 A
I = 10 mA
