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An 850.0 kg car wants to accelerate from rest to a speed of 18.0 m/s.

It has a useful power output of 47.0 hp (1 hp = 746 W).

Neglecting friction.

How much work must the car's engine produce to achieve this increase in speed? DON"T use schientific notation when entering your answers. Hint: Consider the work-kinetic energy theorem.

Respuesta :

Answer:

[tex] 1.07*10^5 Joules [/tex]

Explanation:

From Kinetic energy K.E = m*[tex]v^2[/tex]/2

Where mass of the car, m = 850 kg

velocity of the car, v = 18 m/s

Hence K.E = [tex] 850*18^2/2 = 1.07*10^5 Joules [/tex]

Also, we can evaluate the given time

time = K.E / Power

= [tex] 1.07*10^5 / (50*746) [/tex]

= 2.87 secs

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