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Radium-226 is a radioactive substance with an annual decay rate of 0.04 % . A series of coal mines in Poland contain an abundance of the aforementioned isotope of radium. If these coal mines contained 400 thousand kilograms of radium-226 in 1937, then how much radium-226 would be left in those coal mines in 2017? Round your answer to the nearest kilogram.

Respuesta :

Answer:

i.e. 393650 kg.

Step-by-step explanation:

Given that Radium-226 is a radioactive substance with an annual decay rate of 0.04 %

Let the year 1937 be 0 year

Initially population was = 400,000 kg

Since decay rate is 0.04% per year after t years population would be

[tex]P(t) = 400,000 (1-0.0004)^t[/tex]

=[tex]400,000*0.9996^t[/tex]

In 2017, t = 40 years (i.e. years lapsed form 1937)

Hence population

= [tex]P(40) = 400,000 (0.9996)^{40} \\=393649.66[/tex]

i.e. 393650 kg.

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