Respuesta :
Answer:
The system of equations is:
[tex]M_A(t)=300(0.9985)^t\\ \\ M_B(t)=500(0.9963)^t[/tex]
Explanation:
A. Substance A.
For substance A the rate of decay is 0.15% per year meaning that every year the mass is multiplied by a factor of 1 -0.15/100 = 1 - 0.0015.
Thus, as they have initially 300 g of substance A, its mass can be modeled by the function:
- [tex]M_A(t)=300(1-0.0015)^t=300(0.9985)^t[/tex]
Where [tex]M_A(t)[/tex] is the mass as a function of time, and t is the number of years elapsed.
B. Substance B.
For substance B the rate of decay is 0.37% per year meaning that every year the mass is multiplied by a factor of 0.37/100 = 0.0037.
As they have initially 500 g of substance B, its mass can be modeled by the function:
- [tex]M_B(t)=500(1-0.0037)^t=500(0.9963)^t[/tex]
Where [tex]M_B(t)[/tex] is the mass as a function of time, and t is the number of years elapsed.
C. System of equations:
[tex]M_A(t)=300(0.9985)^t\\ \\ M_B(t)=500(0.9963)^t[/tex]
If you make [tex]M_A(t)=M_B(t)\\ \\ 300(0.9985)^t=500(0.9963)^t[/tex]
You can solve for t, the time when the sustances have equal mass.