Answer:
0.104 M
Explanation:
For the titration of an acid and a base , the relation between the molarity and volume is as follows -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base ,
V₂ = Volume of base ,
from , the question ,
M₁ = ?
V₁ = 50.0 mL
M₂ = 0.1510 M
V₂ = 34.62 mL
Using the above formula , the molarity of the stock solution , can be calculated as ,
M₁V₁ = M₂V₂
M₁ * 50.0 mL = 0.1510 M * 34.62 mL
M₁ = 0.1510 M * 34.62 mL / 50.0 mL
M₁ = 0.104 M
