Respuesta :
Answer:
41.053 A
Explanation:
given,
three phase kVA = 25-kVA
voltage = 440 Volt
current = ?
To determine three phase kVA when volts and amperes are know
three phase kVA = 1.73 x V x I
[tex]I = \dfrac{three\ phase\ kVA}{1.73 \times V}[/tex]
[tex]I = \dfrac{25000}{1.73 \times 440}[/tex]
I = 32.84 A
the maximum overcurrent protection value is equal to
= 125 % of I
= 1.25 x 32.84
= 41.053 A
Maximum overcurrent protection(MOP) is the maximum circuit breaker size required to protect the equipment. The maximum overcurrent protection is 41.053 A.
What is the maximum overcurrent protection (MOP)?
The maximum circuit breaker size required to properly protect the equipment under uncertain fault conditions is known as the maximum overcurrent protection (MOP).
We know that for a three-phase transformer the current can be written as,
[tex]I =\dfrac{\rm 3-phase\ kV\ A}{1.73 \times V}\\\\ I = \dfrac{25000}{1.73 \times 440}\\\\I = 32.84\rm\ A[/tex]
Now, the maximum overcurrent protection value is 25% above the current, therefore, the maximum overcurrent protection can be written as,
[tex]I_{Max} = 125\% \ of \ I[/tex]
[tex]= 1.25 \times 32.84\\\\=41.053\rm\ A[/tex]
Hence, the maximum overcurrent protection is 41.053 A.
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