Answer:
The speed of the white puck immediately after the collision is 2.6 m/s.
Explanation:
Given that,
Two pucks are equal masses.
Speed of black puck = 1.5 m/s
According to given figure,
We need to calculate the speed of the white puck immediately after the collision
Using law of conservation of momentum
[tex]mv=m_{1}v_{1}\cos\theta+m_{2}v_{2}\cos\theta[/tex]
Put the value into the formula according to figure
[tex]m\times3=m\times v_{1}\times\cos30+m\times1.5\times\cos60[/tex]
[tex]3m=0.866m v_{1}+0.75m[/tex]
[tex]v_{1}=\dfrac{3-0.75}{0.866}[/tex]
[tex]v_{1}=2.6\ m/s[/tex]
Hence, The speed of the white puck immediately after the collision is 2.6 m/s.
