To get an idea how big a farad is, suppose you want to make a 1-F air-filled parallel-plate capacitor for a circuit you are building. To make it a reasonable size, suppose you limit the plate area to What would the gap have to be between the plates? Is this practically achievable?

Respuesta :

Answer:

  • Gap between the plates [tex]8.85\times 10^{- 16}\ m[/tex]
  • No, practically not achievable

Solution:

As per the question:

Capacitance, C = 1 F

Area of the plate of the capacitor, A = [tex]1\ cm^{2} = 1\times 10^{- 4}\ m^{2}[/tex]

Now,

To calculate the distance, D between the plates of a parallel plate capacitor:

[tex]C = \frac{\epsilon_{o}A}{D}[/tex]

Thus

[tex]D = \frac{\epsilon_{o}A}{C}[/tex]

where

[tex]\epsilon_{o}[/tex] = permittivity of free space

Now,

[tex]D = \frac{8.85\times 10^{- 12}\times 1\times 10^{- 4}}{1}[/tex]

[tex]D = 8.85\times 10^{- 16}\ m[/tex]

This distance much smaller and is practically not possible