Answer:
Solution:
As per the question:
Capacitance, C = 1 F
Area of the plate of the capacitor, A = [tex]1\ cm^{2} = 1\times 10^{- 4}\ m^{2}[/tex]
Now,
To calculate the distance, D between the plates of a parallel plate capacitor:
[tex]C = \frac{\epsilon_{o}A}{D}[/tex]
Thus
[tex]D = \frac{\epsilon_{o}A}{C}[/tex]
where
[tex]\epsilon_{o}[/tex] = permittivity of free space
Now,
[tex]D = \frac{8.85\times 10^{- 12}\times 1\times 10^{- 4}}{1}[/tex]
[tex]D = 8.85\times 10^{- 16}\ m[/tex]
This distance much smaller and is practically not possible