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A string is stretched between two trees so that it is initially horizontal. When a bird lands in the middle of the string and comes to rest (deflecting the string down a tiny bit in the middle), the tension in the string will:

Respuesta :

Answer:

 [tex]T=\dfrac{wt}{2}[/tex]

Explanation:

Lets take weight of the bird = wt

Tension in the string = T

2 T cosθ = wt

As we know that  

If angle θ is so small then we can say that

cosθ = 1

⇒2 T x 1  = wt  

2 T = wt

[tex]T=\dfrac{wt}{2}[/tex]

Therefore the tension in the string will be half of the weight.

Ver imagen AbsorbingMan

Answer:

T = Mg / (2 CosФ)

Explanation:

Let m be the mas of the bird T be the tension and Ф be the angle between the string and the vertical.

According to the diagram, the components of the tension force

T CosФ + T Cos Ф = Mg

2T CosФ = Mg

T = Mg / (2 CosФ)

Ver imagen Vespertilio

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