Respuesta :
Answer:
u= 187.61 ft/s
Explanation:
Given that
g= - 32 ft/s²
The maximum height ,h= 550 ft
Lets take the initial velocity = u ft/s
We know that
v²=u² + 2 g s
v=final speed ,u=initial speed ,s=height
When the object reach at the maximum height then the final speed of the object will become zero.
That is why
u²= 2 x 32 x 550
u²= 35200
u= 187.61 ft/s
That is why the initial speed will be 187.61 ft/s
Answer:
Explanation:
a = - 32 ft/s²
h = 550 ft
Let the initial velocity is u. The velocity at maximum height is zero.
use third equation of motion
v² = u² + 2 a h
0 = u² - 2 x 32 x 550
u² = 35200
u = 187.62 ft/s
