Name a point that is the square root of 2 away from(-1,5)

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kenlingdad kenlingdad · Answer 1 · 2020-01-22T01:13:01+01:00

Answer:

Any point on the circle (x + 1)² + (y - 5)² = 2 with center (-1 , 5) and radius √2

Step-by-step explanation:

circle: (x + 1)² + (y - 5)² = 2

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shivishivangi1679 shivishivangi1679 · Answer 2 · 2022-08-18T08:49:06+02:00

Any point on the circle of equation(x + 1)² + (y - 5)² = 2 with center (-1 , 5) and radius √2.

A circle can be characterized by its center's location and its radius's length.

Let the center of the considered circle be at (h,k) coordinate.

The radius of the circle be 'r' units.

Then, the equation of that circle would be:

(x-h)^2 + (y-k)^2 = r^2

We have to Name a point that is the square root of 2 away from(-1,5).

So, the equation of that circle would be:

(x + 1)² + (y - 5)² = 2

Hence, Any point on the circle of equation(x + 1)² + (y - 5)² = 2 with center (-1 , 5) and radius √2.

Learn more about equation of a circle here:

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