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1. A ball is thrown straight up into the air with an initial speed of 8.0 m/s.
a. How long does it take for the rocket to reach its highest point?
b. What is the maximum height the ball reaches above the ground?​

Respuesta :

bhuvna789456
  • The Time taken to reach the highest point is t = 0.816 s.
  • The maximum height of the ball is 3.26 m.

Explanation:

When an object falls freely, it falls due to the influence of gravity and this free falling object is called as acceleration of gravity. The free falling object has an acceleration value of about 9.8 m / s^2 downward on Earth.

The Acceleration of Gravity is denoted by a symbol g.

Solution:  

Initial speed = 8.0 m / s.

a. To calculate the time taken, (initial velocity is 8.0 m/s and the final velocity        is 0)

                                     T = Velocity / gravity

Time taken to reach highest point t = 8 / 9.8 = 0.816 s.

b. To calculate the height, (initial velocity is 8.0 m/s and the final velocity is   0)

                                    h = square of velocity / (2 * g)

The maximum height the ball reaches h = (8 * 8) / (2 * 9.8)

                                                                    = 64 / 19.6 = 3.26 m.

                                                                         

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