Answer:
1. [tex]s=-vt^2[/tex]
2. [tex]v=\frac{s}{t}[/tex]
3. [tex]a=-2\times \frac{s}{t}[/tex]
Explanation:
Given:
Acceleration as a Function of velocity, [tex]a=-2v\ m.s^{-2}[/tex]
Velocity, [tex]v=20\ m.s^{-1}[/tex] at displacement s=0 and t=0
1.
Particles position as a function of time:
Using equation of motion:
[tex]s=u.t+\frac{1}{2} a.t^2[/tex]
where:
[tex]u =[/tex] initial velocity
[tex]v=[/tex] final velocity
so,
[tex]s=0+\frac{1}{2}\times (-2v) t^2[/tex]
[tex]s=-vt^2[/tex]
2.
Particle velocity as a function of time:
[tex]v=\frac{s}{t}[/tex]
3.
Particles acceleration as a function of time:
[tex]a=-2\times \frac{s}{t}[/tex]
