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A particle moves in a straight line with the given velocity v(t) = 2t−2 − 2 (in meters per second). Find the displacement and distance traveled over the time interval [0.5, 2].

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erolkayacan

Answer:

The answer is -2.25 units.

Explanation:

Total displacement of particle moves in a straight line with the given velocity v(t) = 2t−2 − 2 will be:

[tex]x=\int\limits^2_{0.5} {2t-2-2} \, dt\\x=\int\limits^2_{0.5} {2t} \, dt+ \int\limits^2_{0.5} {-4}\, dt \\x=3.75-6\\x=-2.25[/tex]

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