Respuesta :
Sarah bought 4 first class tickets and 4 coach tickets.
Step-by-step explanation:
Given,
Number of people on trip = 8
Cost of each coach ticket = $290
Cost of each first class ticket = $980
Total budget for tickets = $5080
Let,
c represent the number of coach tickets
f represent the number of first class tickets
According to given statement;
c+f=8 Eqn 1
290c+980f=5080 Eqn 2
Multiplying Eqn 1 by 290
[tex]290(c+f=8)\\290c+290f=2320\ \ \ eqn\ 3[/tex]
Subtracting Eqn 3 from Eqn 2
[tex](290c+980f)-(290c+290f)=5080-2320\\290c+980f-290c-290f=2760\\690f=2760[/tex]
Dividing both sides by 690
[tex]\frac{690f}{690}=\frac{2760}{690}\\f=4[/tex]
Putting f=4 in Eqn 1
[tex]c+4=8 \\c=8-4\\c=4[/tex]
Sarah bought 4 first class tickets and 4 coach tickets.
Keywords: linear equation, elimination method
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