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The boiling point of ethanol is 78 °C. The molar heat(i.e., enthalpy)of vaporization of ethanol is 38.6 x 103J/mol. What is the molar entropyof vaporization of ethanol?

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Answer:

109.97JK-1

Explanation:

Entropy is the degree of disorderliness of a substance. It is given by ∆H/T where T is the absolute temperature in Kelvin.

Given ∆H= 38.6*10^3

T=78°C+ 273=351K

∆S=38.6*10^3/351=109.97JK-1 as shown the diagram.

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