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HELPPPPP ILL MARK BRAINLIESTT Which could be the function graphed below? On a coordinate plane, a curve opens down and to the right in quadrants 1 and 4. The curve starts on the y-axis in quadrant 4 and goes through the x-axis into quadrant 1. f (x) = StartRoot x EndRoot minus 2 f (x) = StartRoot x minus 3 EndRoot + 1 f (x) = StartRoot 2x + 4 EndRoot f (x) = StartRoot x + 1 EndRoot + 8

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sqdancefan

Answer:

  f(x) = StartRoot x EndRoot minus 2

Step-by-step explanation:

The curve shown below seems to match your description.

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Any square root function with a quantity added to it will not have any presence in quadrant 4, as its graph will be entirely above the x-axis.

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xzaviorhaines

Answer:

It is the first one. I just took the test on edg.

Step-by-step explanation:

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