(35 Points)
Evaluate ƒ(x) when x = 6.

The value of the function is 6
Step-by-step explanation:
The function that we have in this problem is
[tex]f(x)=\left \{ {{3x^2+1}, -4<x<6 \atop {6}, 6\leq x <9} \right.[/tex]
This means that:
when x is between -4 (excluded) and 6 (excluded), the value of the function is [tex]3x^1+2[/tex]
when x is between 6 (included) and 9 (excluded), the value of the function is 6
In this problem, we are asked to evaluate f(x) when x = 6. Therefore, we are in the second case: therefore, the value of the function is 6,
[tex]f(x)=6[/tex]
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