The distance travelled in 5 seconds is 125 m
Explanation:
The motion of the skydiver is a free fall motion, since he is acted upon the force of gravity only. Therefore, it is a uniformly accelerated motion, with constant acceleration downward, and we can find the distance he travels by using the following suvat equation:
[tex]s=ut+\frac{1}{2}at^2[/tex]
where
s is the distance travelled
u is the initial velocity
t is the time
a is the acceleration
In this problem, we have:
u = 0 (the skydiver jumps from rest)
[tex]a=g=10 m/s^2[/tex] (acceleration of gravity)
And substituting
t = 5.0 s
we find the distance travelled:
[tex]s=0+\frac{1}{2}(10)(5)^2=125 m[/tex]
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