A cylindrical roller 2.5 m in length, 1.5 m in radius when rolled on a road was found to cover the area of 16500 m2 . How many revolutions does it make ?

Respuesta :

Answer:

701 revolutions

Step-by-step explanation:

Given: Length= 2.5 m

            Radius= 1.5 m

            Area covered by roller= 16500 m²

Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.

Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.

Formula; Lateral surface area of cylinder= [tex]2\pi rh[/tex]

Considering, π= 3.14

⇒ lateral surface area of cylinder= [tex]2\times 3.14\times 1.5\times 2.5[/tex]

⇒ lateral surface area of cylinder= [tex]23.55 \ m^{2}[/tex]

Area covered by cylindrical roller in one revolution is 23.55 m²

Next finding total number of revolution to cover 16500 m² area.

Total number of revolution= [tex]\frac{16500}{23.55} = 700.6369 \approx 701[/tex]

Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.