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A circular-motion addict of mass 90 kg rides a Ferris wheel around in a vertical circle of radius 10 m at a constant speed of 6.3 m/s. (a) What is the period of the motion?

Respuesta :

abiolaraymond1995

Answer:

9.97sec

Explanation:

To solve for the period we can derive the formula as follows

ω=2πf

ω=2π/T

v=rω

v=2πr/T

T=2πr/v

[tex]T=\frac{2*3.142*10}{6.3}[/tex]

T=9.97sec

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