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The equilibrium A<=' B + Cat 25°C is subjected to a temperature jump which slightly increases the concentrations ofB and C. The measured relaxation time is 3.0 µs. The equilibrium constant for the system is 2.0 x 10 '" 16 at the newtemperature. and th e equilibrium concentrations ofBand C then are both 0.20 mmol dm-). Calculate the rate constants fo r the forward and reverse stepsgiven that the forward s tep is first-order in A, and the reverse step is first-order in both Band C.

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israelsanchez21

Answer:K = [C][D]^2 / [A][B] =  

= 2.4 x 10^-6 ( 3.5 x 10^-3)^2 /( 2.0x10^-2 ) (1.7 x 10^-4) = 8.65 x 10^-6

8.65 x 10^-6 < 3.7 x 10^-3

The system is not at equilibrium and the reaction will shift on the right.

The answer is 4

Explanation:

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