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Element X has two naturally-occurring isotopes. X-10 has a 19.9% abundance and X-11 has an 80.1% abundance. What is most likely the identity of element X?

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Answer:

The identity of element X is Boron (R.A.M =10.81)

Explanation:

We are given;

Element X,

  • First Isotope, X-10, with an abundance of 19.9%
  • Second isotope, X-11 with an abundance of 80.1%

We are required to identify the element X

  • To identify the element we need to determine it R.A.M.

Then, how do we get R.A.M of an element?

R.A.M. = ((Mass of isotope-1 × R. abundance) + (mass of isotope-2 × R. abundance)) ÷ 100

Therefore, in this case;

R.A.M. of X = ((mass of X-10 × R.abundance) + (mass of x-11 × R. abundance))÷ 100

Thus;

R.A.M of X = ((10 × 19.9) + (11 × 80.1)) ÷ 100

                 = 10.81

Thus, the relative atomic mass of X is 10.81.

The identity of element X is Boron. (Boron has an R.A.M of 10.81)

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