Answer:
a. [tex]Change in Voltage=12*10^{4}V[/tex]
b. [tex]Change in Voltage=12*10^{4}V[/tex]
Explanation:
The work done in moving an electric charge round a circuit is express as
[tex]workdone=voltage*charge \\Wd=v*q[/tex]
The voltage is in-turn define as the electric potential energy per unit charge.
[tex]Voltage=\frac{potitntial energy }{charge}\\[/tex]
a. for a 12J work done on a charge of value 0.0001C, we can compute the voltage change as
[tex]Voltage=\frac{potitntial energy }{charge}\\Voltage=\frac{12J}{0.0001C}\\ Voltage=12,0000J/C\\ Change in Voltage=12*10^{4}V[/tex]
a. for a 24J work done on a charge of value 0.0002C, we can compute the voltage change as
[tex]Voltage=\frac{potitntial energy }{charge}\\Voltage=\frac{24J}{0.0002C}\\ Voltage=12,0000J/C\\Change in Voltage=12*10^{4}V[/tex]
The voltage change in (a) is 1.2 × 10⁵ J/C and in (b) is 1.2 × 10⁵ J/C.
a) Based on the given information,
• Work done (W) is 12 J and charge (q) is 0.0001 C.
The change in voltage is determined by using the formula,
= W/q
Now putting the values we get,
= [tex]\frac{12}{0.0001} J/C[/tex] or 1.2 × 10⁵J/C
b) Based on the given information,
• Work done (W) is 24J and charge (q) is 0.0002 C.
The change in voltage can be calculated as,
= W/q
Putting the values we get,
=[tex]\frac{24}{0.0002} J/C[/tex] or 1.2 × 10⁵J/C
Thus, the voltage change in both the conditions is 1.2 × 10⁵J/C.
To know more about:
https://brainly.com/question/14529111
