Answer:
b. E (about 329 Hz)
Explanation:
Given data:
Initial length of the string l1= 24 in
initial frequency f1= 247 Hz
changed length l2= 18 in
Then we have to find the changed frequency f2= ?
We already now that
frequency f ∝ 1/length of the string l
therefore,
[tex]\frac{f_1}{f_2} =\frac{l_1}{l_2}[/tex]
⇒[tex]{f_2}=\frac{l_1}{l_2}\times{f_1}[/tex]
⇒[tex]{f_2}=\frac{24}{18}\times{247}[/tex]
⇒[tex]{f_2}=329.33 Hz[/tex]