Respuesta :

Answer:

[tex]T=0.02\ s[/tex]

[tex]f=50\ Hz[/tex]

Explanation:

Given:

  • minimum amplitude at the start of oscillation cycle, [tex]a_0=20\ unit[/tex]
  • the first maximum amplitude after the start of oscillation cycle, [tex]a_{m1}=100\ units[/tex]
  • Time taken to reach from the first minima to the first maxima, [tex]t=5\times 10^{-3}\ s[/tex]

As we know that an oscilloscope executes a wave cycle represented by a sine wave. So we can deduce that it  has executed one-fourth of the cycle in going from the amplitude of 20 units to 100 units in 0.005 seconds.

So the time taken to complete one cycle of the oscillation:

[tex]T=4\times 0.005[/tex]

[tex]T=0.02\ s[/tex] is the time period of the oscillation

We know frequency:

[tex]f=\frac{1}{T}[/tex]

[tex]f=\frac{1}{0.02}[/tex]

[tex]f=50\ Hz[/tex]

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