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Convert grams of FeCl2 to moles. Then rearrange M = n/V to solve for V: V = n/M (in Liters) What volume of a 0.01 M solution can be made using 120 grams of FeCl2?

Respuesta :

joseaaronlara

Answer:

The answer to your question is Volume = 214.3 ml

Explanation:

Data

mass = 120 g of FeCl₂

concentration = 0.01 M

volume = ?

Formula

Molarity = [tex]\frac{number of moles}{volume}[/tex]

Solve for volume

Volume = [tex]\frac{number of moles}{molarity}[/tex]

Process

1.- Convert grams to moles

Atomic weight = 56 g

                            56 g of Fe --------------- 1 mol

                         120 g of Fe  ----------------  x

                               x = (120 x 1) / 56

                               x = 2.14 moles

2.- Calculate the volume

Volume = [tex]\frac{2.14}{0.01}[/tex]

Volume = 214.3 ml

Answer:

We need 94.67 liters if a 0.01 M solution

Explanation:

Step 1: Data given

Molarity of the solution = 0.01 M

Mass of FeCl2 = 120.0 grams

Molar mass FeCl2 = 126.75 g/mol

Step 2: Calculate moles of FeCl2

moles FeCl2 = massFeCl2 / molar mass FeCl2

Moles FeCl2 = 120.0 grams / 126.75 g/mol

Moles FeCl2 = 0.9467 moles

Step 3: Calculate  volumes FeCl2

Molarity = moles / volume

Volume = moles / molarity

Volume = 0.9467 moles /0.01 M

Volume = 94.67 L

We need 94.67 liters if a 0.01 M solution

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